Preparation and standardization of 0.05 M Silver Nitrate EP Volumetric Solution

1.  PREPARATION:

Dissolve 8.5 g of silver nitrate in 1000 mL carbon dioxide free water.

2. STANDARDISATION:

Dissolve 25 mg of Sodium chloride in water, add 5 mL of dilute nitric acid and dilute to 50 mL with water. Titrate with Silver nitrate solution, determining the end point potentiometrically.

1 mL of 0.05 M Silver Nitrate is equivalent to 0.5844 mg of NaCl.

Calculation :

Molarity (M) = [0.05 x Weight of NaCl (in mg)]/ [Titration reading (in mL) x 0.5844]                                           

Limit: 0.05 M ± 5 % (0.0475 M – 0.0525 M)

3. PREPARATION OF INDICATORS / REAGENTS:

Dilute nitric acid:

Dilute 20 g of nitric acid to 100 mL with water

4. STORAGE CONDITION:

Store in amber glass stoppered bottles. (Protect from light)