Preparation and Standardisation of 0.01 M Silver Nitrate EP Volumetric Solution
Dissolve 1.7 g of Silver Nitrate in water and dilute to 1000 ml with the same solvent.
Accurately weigh and dissolve 20 mg of Sodium chloride in 30 ml of water and Titrate with the Silver Nitrate solution determining the end point potentiometrically.
1 ml of 0.01 M Silver Nitrate is equivalent to 0.5844 mg of NaCl.
Molarity (M) = (0.01 x Weight of NaCl (in mg))/ Titration reading (in ml) x 0.5844
Limit: 0.01 M ± 5 % (0.0095 M – 0.0105 M)
3. STORAGE CONDITION:
Store in glass stoppered bottles, protected from light.